A drop of mercury of radius 0.2 cm is broken into 8 droplets of the same size. Find the work done if the surface tension of mercury is 435.5 dyne/cm

Please read the guide .

Thanks for contributing an answer!

\(........\)

Avoid writing here -

Answer:: 2.19 x 10^{-5} J

Explaination::

Given :: R = 0.2 cm, n = 8, T = 435.5 dyn/cm

As the volume of the liquid remains constant, volume of n droplets = volume of the drop

4.8k questions

4.3k answers

67 comments

387 users