The pressure of water inside the closed pipe is 3 x10^{5} N/m^{2}. This pressure reduces to 2 x10^{5} N/m^{2} on opening the value of the pipe. Calculate the speed of water flowing through the pipe. (Density of water = 1000 kg/m^{3})

Please read the guide .

Thanks for contributing an answer!

\(........\)

Avoid writing here -

Correct answer = 14.14 m/s

Explaination::

Given:: p_{1} = 3 × 10^{5} Pa, v_{1} = 0, p_{2} = 2 × 10^{5} Pa, ρ = 10^{3} kg/m^{3}

Assuming the potential head to be zero, i.e., the pipe to be horizontal, the Bernoulli equation is

For amazing tutorial videos, podcasts, hindi tutorials

4.1k questions

3.6k answers

50 comments

376 users