Correct answer = 1250 N
Explaination::
Given : A_{1 }= 30 cm^{2 }= 3×10^{-3} m^{2} , A_{2} = 1500 cm^{2 }= 0.15 m^{2 }F_{1}=25 N
By Pascal’s law
\(\frac{F1}{A1}=\frac{F2}{A2}\)
∴The force on the output piston,
\(F2=F1(\frac{A2}{A1})\)
= \((25)\frac{0.15}{3×10^3} \)=25 × 50=1250 N
Weight on output piston = 1250 N