**In a hydraulic lift, the input piston had surface area 30 cm ^{2} and the output piston has surface area of 1500 cm^{2}. If a force of 25 N is applied to the input piston, calculate weight on output piston. **

**Correct answer = 1250 N**

**Explaination::**

**Given : **A_{1 }= 30 cm^{2 }= 3×10^{-3} m^{2} , A_{2} = 1500 cm^{2 }= 0.15 m^{2 }F_{1}=25 N

By Pascal’s law

\(\frac{F1}{A1}=\frac{F2}{A2}\)

∴The force on the output piston,

\(F2=F1(\frac{A2}{A1})\)

= \((25)\frac{0.15}{3×10^3} \)=25 × 50=**1250 N**

**Weight on output piston = 1250 N**