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In a hydraulic lift, the input piston had surface area 30 cm2 and the output piston has surface area of 1500 cm2. If a force of 25 N is applied to the input piston, calculate weight on output piston. 

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Correct answer = 1250 N

Explaination::

Given : A= 30 cm= 3×10-3 m2 , A2 = 1500 cm= 0.15 mF1=25 N

By Pascal’s law

\(\frac{F1}{A1}=\frac{F2}{A2}\)

∴The force on the output piston,

\(F2=F1(\frac{A2}{A1})\)

= \((25)\frac{0.15}{3×10^3}  \)=25 × 50=1250 N

Weight on output piston = 1250 N

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