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Find the pressure 200 m below the surface of the ocean if pressure on the free surface of liquid is one atmosphere. (Density of sea water = 1060 kg/m3)

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Correct Answer=  21.789×105  N/m2 

Explaination::

Given : h=200 m, ρ=1060 kg/mp= 1.013×10Pa, g = 9.8 m/s2

Absolute pressure,

Solution::

P=p0+hρg

= (1.013×10)+(200×1060×9.8)

= (1.013×10)+(20.776×105)

= 21.789×105  N/m2 

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