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A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?

  • A) A screw gauge having 100 divisions in the circular scale and pitch as 1 mm.
  • B) A screw gauge having 50 divisions in the circular scale and pitch as 1 mm.
  • C) A meter scale.
  • D) A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm.
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Measured length of rod = 3.50 cm
That means least count of the measuring instrument should be 0.01 cm = 0.1 mm
For vernier scale 1 main scale division = 1 mm
And 9 MSD = 10 VSD
Least count = 1 MSD - 1 VSD
= 1 - 0.9 = 0.1 mm
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